A flywheel in the form of a uniformly thick disk 4ft in diameter weighs 600lbs and rotates at 1200 rpm. Calculate the constant torque necessary to stop it in 2.0 min.
Text Solution
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Sol. The equation of motion for the flywheel is
,
Where I is the moment of inertia and M is the stopping torque. Hence
.
When the flywheel stops at time t, 
and
M = 
.
With I = 
= 1200 lb ft 2 , ω 0 = 40 π rad/s,
t = 120s
M = 400 π pdl ft = 39 lb ft.
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